26) \(\frac{4c^3}{(x-y)} \cdot \frac{(x-y)^2}{40c}\)

Решение:

Перемножим числители и знаменатели:

\( \frac{4c^3}{(x-y)} \cdot \frac{(x-y)^2}{40c} = \frac{4c^3 \cdot (x-y)^2}{(x-y) \cdot 40c} \)

Сократим дробь:

\( \frac{\cancel{4}^1 c^{\cancel{3}}^2 \cancel{(x-y)}^{\cancel{2}}^1}{\cancel{(x-y)}^1 \cdot \cancel{40}^10 \cancel{c}^1} = \frac{c^2 \cdot (x-y)}{1 \cdot 10} = \frac{c^2(x-y)}{10} \)

Ответ: \(\frac{c^2(x-y)}{10}\)