7. Найдите значение выражения
- $$\left(\sqrt{28}-\sqrt{7}\right)\cdot\sqrt{7}$$;
$$\left(\sqrt{28}-\sqrt{7}\right)\cdot\sqrt{7} = \left(\sqrt{4\cdot7}-\sqrt{7}\right)\cdot\sqrt{7} = \left(2\sqrt{7}-\sqrt{7}\right)\cdot\sqrt{7} = \sqrt{7}\cdot\sqrt{7} = 7$$
- $$\sqrt{7}\cdot 12\cdot \sqrt{21}$$;
$$\sqrt{7}\cdot 12\cdot \sqrt{21} = 12\cdot\sqrt{7\cdot21} = 12\cdot\sqrt{7\cdot7\cdot3} = 12\cdot7\cdot\sqrt{3} = 84\sqrt{3}$$
- $$\frac{\sqrt{30}\cdot\sqrt{15}}{\sqrt{18}}$$;
$$\frac{\sqrt{30}\cdot\sqrt{15}}{\sqrt{18}} = \frac{\sqrt{30\cdot15}}{\sqrt{18}} = \frac{\sqrt{2\cdot15\cdot15}}{\sqrt{2\cdot9}} = \frac{15\sqrt{2}}{3\sqrt{2}} = \frac{15}{3} = 5$$
- $$4\sqrt{13}\cdot 2\sqrt{3}\cdot \sqrt{39}$$;
$$4\sqrt{13}\cdot 2\sqrt{3}\cdot \sqrt{39} = 8\sqrt{13\cdot3\cdot39} = 8\sqrt{13\cdot3\cdot3\cdot13} = 8\cdot13\cdot3 = 312$$
- $$\sqrt{7^4}$$;
$$\sqrt{7^4} = 7^2 = 49$$
- $$\sqrt{9^5}$$
$$\sqrt{9^5} = \sqrt{9^4\cdot9} = 9^2\sqrt{9} = 81\cdot3 = 243$$
Ответ:
- 7
- $$84\sqrt{3}$$
- 5
- 312
- 49
- 243