294 1) 3 3 log3 8 log3 16 log5 27 -; 2) ; 3) log5 9 3 log5 36-log512 log59 log 78 ; 4) log 715-log7 30

1) $$ \frac{log_3 8}{log_3 16} = log_{16} 8 = log_{2^4} 2^3 = \frac{3}{4}$$

2) $$ \frac{log_5 27}{log_5 9} = log_9 27 = log_{3^2} 3^3 = \frac{3}{2}$$

3) $$ \frac{log_5 36 - log_5 12}{log_5 9} = \frac{log_5 \frac{36}{12}}{log_5 9} = \frac{log_5 3}{log_5 3^2} = \frac{log_5 3}{2 log_5 3} = \frac{1}{2}$$

4) $$ \frac{log_7 8}{log_7 15 - log_7 30} = \frac{log_7 8}{log_7 \frac{15}{30}} = \frac{log_7 8}{log_7 \frac{1}{2}} = \frac{log_7 2^3}{log_7 2^{-1}} = \frac{3 log_7 2}{-log_7 2} = -3$$

Ответ: 3/4; 3/2; 1/2; -3