14. \(\frac{a^{18} \cdot (b^7)^2}{(a \cdot b)^{14}}\) при a = 3 и b = \(\sqrt{3}\)

\(\frac{a^{18} \cdot (b^7)^2}{(a \cdot b)^{14}} = \frac{a^{18} \cdot b^{14}}{a^{14} \cdot b^{14}} = a^{18-14} = a^4\). При \(a = 3\), \(3^4 = 81\). Ответ: 81