Ответ:\(\frac{x^2+y^2}{x^4}=\frac1{x^2}+\frac{y^2}{x^4}\).\(\frac{2x-y}{b}=\frac{2x}{b}-\frac yb\).\(\frac{a^2+1}{2a}=\frac a2+\frac1{2a}\).\(\frac{a^2-3ab}{a^3}=\frac1a-\frac{3b}{a^2}\).