1) Вычислить: а) √196–4√0,64; б) √13 1/3 * √2 7/10 ; в) √3⁶ * 5² ; г) √180-√32 / √40.

а) \(\sqrt{196} - 4\sqrt{0.64} = 14 - 4 * 0.8 = 14 - 3.2 = 10.8\) б) \(\sqrt{13 \frac{1}{3}} \cdot \sqrt{2 \frac{7}{10}} = \sqrt{\frac{40}{3}} \cdot \sqrt{\frac{27}{10}} = \sqrt{\frac{40 \cdot 27}{3 \cdot 10}} = \sqrt{\frac{4 \cdot 9}{1}} = \sqrt{36} = 6\) в) \(\sqrt{3^6 \cdot 5^2} = \sqrt{(3^3)^2 \cdot 5^2} = 3^3 \cdot 5 = 27 \cdot 5 = 135\) г) \(\frac{\sqrt{180} - \sqrt{32}}{\sqrt{40}} = \frac{\sqrt{36 \cdot 5} - \sqrt{16 \cdot 2}}{\sqrt{4 \cdot 10}} = \frac{6\sqrt{5} - 4\sqrt{2}}{2\sqrt{10}} = \frac{3\sqrt{5} - 2\sqrt{2}}{\sqrt{10}} = \frac{(3\sqrt{5} - 2\sqrt{2})\sqrt{10}}{\sqrt{10}\sqrt{10}} = \frac{3\sqrt{50} - 2\sqrt{20}}{10} = \frac{3 \cdot 5\sqrt{2} - 2 \cdot 2\sqrt{5}}{10} = \frac{15\sqrt{2} - 4\sqrt{5}}{10}\)