a) \(2\sqrt{7} = \sqrt{4 \cdot 7} = \sqrt{28}\) и \(11\sqrt{2} = \sqrt{121 \cdot 2} = \sqrt{242}\). Так как \(28 < 242\), то \(2\sqrt{7} < 11\sqrt{2}\).
б) \(2\sqrt{\frac{15}{8}} = \sqrt{4 \cdot \frac{15}{8}} = \sqrt{\frac{15}{2}} = \sqrt{7.5}\) и \(\sqrt{\frac{63}{3}} = \sqrt{21}\). Так как \(7.5 < 21\), то \(2\sqrt{\frac{15}{8}} < \sqrt{\frac{63}{3}}\) .