б) $$\frac{1}{6} + 2a - \frac{5}{6}a = \frac{1}{6} + (2 - \frac{5}{6})a = \frac{1}{6} + (\frac{12}{6} - \frac{5}{6})a = \frac{1}{6} + \frac{7}{6}a$$
Ответ: $$\frac{1}{6} + \frac{7}{6}a$$