Решение

1. $$2^2 \cdot 2^3 = 2^{2+3} = 2^5 = 32$$
2. $$3^{15} : 3^{11} = 3^{15-11} = 3^4 = 81$$
3. $$5^9 \cdot 5^3 : 5^{10} = 5^{9+3-10} = 5^2 = 25$$
4. $$11^{11} : 11^{10} \cdot 11 = 11^{11-10+1} = 11^2 = 121$$
5. $$\left(\frac{11}{13}\right)^{17} : \left(\frac{11}{13}\right)^{16} \cdot \frac{11}{13} = \left(\frac{11}{13}\right)^{17-16+1} = \left(\frac{11}{13}\right)^2 = \frac{121}{169}$$
6. $$\frac{7^{15} \cdot 7^{12}}{7^2} = \frac{7^{15+12}}{7^2} = \frac{7^{27}}{7^2} = 7^{27-2} = 7^{25}$$
7. $$\frac{(0,2)^{14} \cdot (0,2)^9}{(0,2)^{15} \cdot (0,2)^6} = \frac{(0,2)^{14+9}}{(0,2)^{15+6}} = \frac{(0,2)^{23}}{(0,2)^{21}} = (0,2)^{23-21} = (0,2)^2 = 0,04$$
8. $$3^2 \cdot 81 = 9 \cdot 81 = 729$$
9. $$256 : 2^5 \cdot 2^2 = 2^8 : 2^5 \cdot 2^2 = 2^{8-5+2} = 2^5 = 32$$
10. $$\frac{6^7}{6^3 \cdot 216} = \frac{6^7}{6^3 \cdot 6^3} = \frac{6^7}{6^6} = 6^{7-6} = 6^1 = 6$$

Ответ:

1. $$32$$
2. $$81$$
3. $$25$$
4. $$121$$
5. $$\frac{121}{169}$$
6. $$7^{25}$$
7. $$0,04$$
8. $$729$$
9. $$32$$
10. $$6$$