6 lcg32x + log3x = 2-

$$log_3^2x+log_3x=2$$

$$log_3^2x+log_3x-2=0$$

$$t=log_3x$$

$$t^2+t-2=0$$

$$t_1=-2, t_2=1$$

$$log_3x=-2 => x=3^{-2}=\frac{1}{9}$$

$$log_3x=1 => x=3$$

Ответ: 1/9; 3