г) x-y. 2 8x y-x

г) $$\frac{x-y}{8x} - \frac{2}{y-x} = \frac{x-y}{8x} + \frac{2}{x-y} = \frac{(x-y)(x-y) + 2 \cdot 8x}{8x(x-y)} = \frac{(x-y)^2 + 16x}{8x(x-y)} = \frac{x^2 - 2xy + y^2 + 16x}{8x(x-y)}$$

Ответ: $$\frac{x^2 - 2xy + y^2 + 16x}{8x(x-y)}$$