Ответ:
1)
\(\sqrt{27}=3\sqrt3\), поэтому
\[(4\sqrt3+\sqrt{27})\sqrt3=(4\sqrt3+3\sqrt3)\sqrt3=7\sqrt3\cdot\sqrt3=21.\]
2)
\[(\sqrt7-\sqrt3)^2=(\sqrt7)^2-2\sqrt7\sqrt3+(\sqrt3)^2=7-2\sqrt{21}+3=10-2\sqrt{21}.\]
Ответ: 1) \(21\); 2) \(10-2\sqrt{21}\).
1)
\(\sqrt{27}=3\sqrt3\), поэтому
\[(4\sqrt3+\sqrt{27})\sqrt3=(4\sqrt3+3\sqrt3)\sqrt3=7\sqrt3\cdot\sqrt3=21.\]
2)
\[(\sqrt7-\sqrt3)^2=(\sqrt7)^2-2\sqrt7\sqrt3+(\sqrt3)^2=7-2\sqrt{21}+3=10-2\sqrt{21}.\]
Ответ: 1) \(21\); 2) \(10-2\sqrt{21}\).