8) $$ \frac{48x^4y^3}{4c} : 16x^2y^3 = \frac{48x^4y^3}{4c} \cdot \frac{1}{16x^2y^3} = \frac{48x^4y^3}{4c \cdot 16x^2y^3} = \frac{48}{4 \cdot 16} \cdot \frac{x^4}{x^2} \cdot \frac{y^3}{y^3} \cdot \frac{1}{c} = \frac{3}{4} \cdot x^2 \cdot 1 \cdot \frac{1}{c} = \frac{3x^2}{c} $$
Ответ: $$\frac{3x^2}{c}$$