3 4x² 18y³:9y⁵

3) $$ 18y^3 : \frac{4x^2}{9y^5} = 18y^3 \cdot \frac{9y^5}{4x^2} = \frac{18y^3 \cdot 9y^5}{4x^2} = \frac{18 \cdot 9}{4} \cdot \frac{y^3 \cdot y^5}{x^2} = \frac{162}{4} \cdot \frac{y^8}{x^2} = \frac{81y^8}{2x^2} $$

Ответ:$$\frac{81y^8}{2x^2}$$