Для треугольника ABC:
\( \angle B = 180^{\circ} - 146^{\circ} = 34^{\circ} \)
\( \angle C = 180^{\circ} - ( \angle A + \angle B) \)
\( \angle C = 180^{\circ} - (34^{\circ} + 34^{\circ}) = 180^{\circ} - 68^{\circ} = 112^{\circ} \)
Ответ: \( \angle B = 34^{\circ} \), \( \angle C = 112^{\circ} \).