Задание 7
Выполним указанные действия с дробями.
- $$\frac{17}{50} \cdot \frac{15}{34} = \frac{17 \cdot 15}{50 \cdot 34} = \frac{17 \cdot 3 \cdot 5}{10 \cdot 5 \cdot 17 \cdot 2} = \frac{3}{10 \cdot 2} = \frac{3}{20}$$
- $$2\frac{4}{21} : 3\frac{2}{7} = \frac{2 \cdot 21 + 4}{21} : \frac{3 \cdot 7 + 2}{7} = \frac{46}{21} : \frac{23}{7} = \frac{46}{21} \cdot \frac{7}{23} = \frac{23 \cdot 2 \cdot 7}{3 \cdot 7 \cdot 23} = \frac{2}{3}$$
- $$\frac{5}{13} \cdot 26 = \frac{5}{13} \cdot \frac{26}{1} = \frac{5 \cdot 26}{13 \cdot 1} = \frac{5 \cdot 13 \cdot 2}{13 \cdot 1} = 5 \cdot 2 = 10$$
- $$9\frac{3}{4} : 11\frac{7}{10} = \frac{9 \cdot 4 + 3}{4} : \frac{11 \cdot 10 + 7}{10} = \frac{39}{4} : \frac{117}{10} = \frac{39}{4} \cdot \frac{10}{117} = \frac{39 \cdot 10}{4 \cdot 117} = \frac{39 \cdot 2 \cdot 5}{2 \cdot 2 \cdot 39 \cdot 3} = \frac{5}{2 \cdot 3} = \frac{5}{6}$$
Ответ:
- $$\frac{3}{20}$$
- $$\frac{2}{3}$$
- $$10$$
- $$\frac{5}{6}$$