Выполните действия: ($$\frac{11}{18}$$-1$$\frac{7}{12}$$)($$2\frac{1}{6}$$+$$\frac{7}{3}$$);

$$\left(\frac{11}{18}-1\frac{7}{12}\right) \cdot \left(2\frac{1}{6}+\frac{7}{3}\right)=\left(\frac{11}{18}-\frac{19}{12}\right)\cdot\left(\frac{13}{6}+ \frac{14}{6}\right)=\left(\frac{22}{36}-\frac{57}{36}\right)\cdot\frac{27}{6}=-\frac{35}{36}\cdot\frac{27}{6}=-\frac{35}{4}\cdot\frac{3}{6}=-\frac{35}{4}\cdot\frac{1}{2}=-\frac{35}{8}=-4\frac{3}{8}$$

Ответ: $$-4\frac{3}{8}$$