$$\left(3\frac{7}{30}-1\frac{5}{12}\right):18\frac{1}{6} = \left(\frac{97}{30}-\frac{17}{12}\right):\frac{109}{6}=\left(\frac{194}{60}-\frac{85}{60}\right):\frac{109}{6}=\frac{109}{60}:\frac{109}{6}=\frac{109}{60}*\frac{6}{109}=\frac{1}{10}$$
Ответ:$$\frac{1}{10}$$