14. Вычислите: \(2 \frac{4}{5} \cdot \frac{9}{16}-\frac{5}{27}:3 \frac{7}{28}\). Запишите полностью решение и ответ.

1) \(2 \frac{4}{5} = \frac{2 \cdot 5 + 4}{5} = \frac{14}{5}\) 2) \(\frac{14}{5} \cdot \frac{9}{16} = \frac{14 \cdot 9}{5 \cdot 16} = \frac{7 \cdot 9}{5 \cdot 8} = \frac{63}{40} = 1 \frac{23}{40}\) 3) \(3 \frac{7}{28} = 3 \frac{1}{4} = \frac{3 \cdot 4 + 1}{4} = \frac{13}{4}\) 4) \(\frac{5}{27} : \frac{13}{4} = \frac{5}{27} \cdot \frac{4}{13} = \frac{5 \cdot 4}{27 \cdot 13} = \frac{20}{351}\) 5) \(1 \frac{23}{40} - \frac{20}{351} = \frac{63}{40} - \frac{20}{351} = \frac{63 \cdot 351 - 20 \cdot 40}{40 \cdot 351} = \frac{22113 - 800}{14040} = \frac{21313}{14040} = 1 \frac{7273}{14040}\) Ответ: 1 7273/14040