1. Вычислить: $$\sin \frac{\pi}{3} - \cos \frac{\pi}{6} + \cos \pi$$.

$$\sin \frac{\pi}{3} = \frac{\sqrt{3}}{2}$$

$$\cos \frac{\pi}{6} = \frac{\sqrt{3}}{2}$$

$$\cos \pi = -1$$

$$\sin \frac{\pi}{3} - \cos \frac{\pi}{6} + \cos \pi = \frac{\sqrt{3}}{2} - \frac{\sqrt{3}}{2} - 1 = -1$$

Ответ: -1