Вариант В2. 3. Вычислите: а) 3/140 + 13/210; б) 41/45 − 0,32; в) (3/16 + 3/10) + (15/32 − 1/24).

1. а) \(\frac{3}{140}+\frac{13}{210}=\frac9{420}+\frac{26}{420}=\frac{35}{420}=\frac1{12}\).
2. б) \(\frac{41}{45}-0{,}32=\frac{41}{45}-\frac8{25}=\frac{205}{225}-\frac{72}{225}=\frac{133}{225}\).
3. в) \(\left(\frac3{16}+\frac3{10}\right)+\left(\frac{15}{32}-\frac1{24}\right)=\frac{39}{80}+\frac{41}{96}=\frac{234}{480}+\frac{205}{480}=\frac{439}{480}\).

Ответ: а) \(\frac1{12}\); б) \(\frac{133}{225}\); в) \(\frac{439}{480}\).