Ответ:При \(p=0.5, q=-0.5\): \(p^2q^2+pq-q^3-p^3=0.0625-0.25+0.125-0.125=-0.1875=-\frac{3}{16}\).При \(x=\frac23, y=\frac12\): \(3x^3-2y^3-6x^2y^2+xy=\frac89-\frac14-\frac23+\frac13=-\frac{11}{36}\).