3. Разложите на множители: a) 16y²-0,25; в) (b+8)²-4b2 д) а² - х²+4x-4. б) а²+10ab + 25b². г) 125-b³. e) 25/169-b⁴

a) $$16y^2 - 0.25 = (4y)^2 - (0.5)^2 = (4y - 0.5)(4y + 0.5)$$ б) $$a^2 + 10ab + 25b^2 = a^2 + 2(a)(5b) + (5b)^2 = (a + 5b)^2$$ в) $$(b+8)^2 - 4b^2 = (b+8)^2 - (2b)^2 = (b+8 - 2b)(b+8 + 2b) = (8 - b)(3b + 8)$$ г) $$125 - b^3 = 5^3 - b^3 = (5 - b)(25 + 5b + b^2)$$ e) $$\frac{25}{169} - b^4 = (\frac{5}{13})^2 - (b^2)^2 = (\frac{5}{13} - b^2)(\frac{5}{13} + b^2)$$ д) $$a^2 - x^2 + 4x - 4 = a^2 - (x^2 - 4x + 4) = a^2 - (x - 2)^2 = (a - (x - 2))(a + (x - 2)) = (a - x + 2)(a + x - 2)$$ Ответ: a) $$(4y - 0.5)(4y + 0.5)$$ б) $$(a + 5b)^2$$ в) $$(8 - b)(3b + 8)$$ г) $$(5 - b)(25 + 5b + b^2)$$ д) $$(a - x + 2)(a + x - 2)$$ e) $$(\frac{5}{13} - b^2)(\frac{5}{13} + b^2)$$