б) $$3x^3 - 1$$ при $$x = -\frac{1}{3}$$:
$$3 \cdot \left(-\frac{1}{3}\right)^3 - 1 = 3 \cdot \left(-\frac{1}{27}\right) - 1 = -\frac{1}{9} - 1 = -\frac{1}{9} - \frac{9}{9} = -\frac{10}{9}$$.
Ответ: $$-\frac{10}{9}$$.