2. Найдите значение выражения: a) \(7-4\frac{5}{9}=\); в) \(6\frac{13}{21}+2\frac{9}{14}=\); б) \(4\frac{3}{10}+1\frac{5}{12}=\); г) \(5\frac{1}{6}-3\frac{3}{4}=\)

Решение:

a) \(7-4\frac{5}{9} = 6\frac{9}{9}-4\frac{5}{9} = (6-4)+(\frac{9}{9}-\frac{5}{9}) = 2 + \frac{4}{9} = 2\frac{4}{9}\)

в) \(6\frac{13}{21}+2\frac{9}{14} = 6\frac{26}{42}+2\frac{27}{42} = (6+2)+(\frac{26}{42}+\frac{27}{42}) = 8+\frac{53}{42} = 8+1\frac{11}{42} = 9\frac{11}{42}\)

б) \(4\frac{3}{10}+1\frac{5}{12} = 4\frac{18}{60}+1\frac{25}{60} = (4+1)+(\frac{18}{60}+ \frac{25}{60}) = 5 + \frac{43}{60} = 5\frac{43}{60}\)

г) \(5\frac{1}{6}-3\frac{3}{4} = 5\frac{2}{12}-3\frac{9}{12} = 4\frac{14}{12}-3\frac{9}{12} = (4-3)+(\frac{14}{12}-\frac{9}{12}) = 1+\frac{5}{12} = 1\frac{5}{12}\)

Ответ: а) \(2\frac{4}{9}\); в) \(9\frac{11}{42}\); б) \(5\frac{43}{60}\); г) \(1\frac{5}{12}\)