Найдите значение выражения: $$\sqrt{a-b}$$ при $$a = \frac{3}{4}$$, $$b = -\frac{1}{18}$$

$$\sqrt{a-b} = \sqrt{\frac{3}{4} - (-\frac{1}{18})} = \sqrt{\frac{3}{4} + \frac{1}{18}} = \sqrt{\frac{27}{36} + \frac{2}{36}} = \sqrt{\frac{29}{36}} = \frac{\sqrt{29}}{6}$$

Ответ: $$\frac{\sqrt{29}}{6}$$