1) $$8\frac{16}{23}-2\frac{12}{23}+3\frac{3}{23}=(8-2+3)+(\frac{16}{23}-\frac{12}{23}+\frac{3}{23})=9+\frac{16-12+3}{23}=9+\frac{7}{23}=9\frac{7}{23}$$
2) $$6\frac{5}{11}-2\frac{2}{11}=(6-2)+(\frac{5}{11}-\frac{2}{11})=4+\frac{5-2}{11}=4+\frac{3}{11}=4\frac{3}{11}$$
3) $$7-4\frac{4}{5}=6\frac{5}{5}-4\frac{4}{5}=(6-4)+(\frac{5}{5}-\frac{4}{5})=2+\frac{5-4}{5}=2+\frac{1}{5}=2\frac{1}{5}$$
4) $$25\frac{8}{9}+76\frac{5}{9}=(25+76)+(\frac{8}{9}+\frac{5}{9})=101+\frac{8+5}{9}=101+\frac{13}{9}=101+1\frac{4}{9}=102\frac{4}{9}$$
5) $$17\frac{2}{5}-5=(17-5)+\frac{2}{5}=12+\frac{2}{5}=12\frac{2}{5}$$
Ответ: 1) $$9\frac{7}{23}$$; 2) $$4\frac{3}{11}$$; 3) $$2\frac{1}{5}$$; 4) $$102\frac{4}{9}$$; 5) $$12\frac{2}{5}$$