г) 35x² + 2x - 1 = 0; д) 2у² - y - 5 = 0; е) 16x² - 8x + 1 = 0.

г) $$35x^2 + 2x - 1 = 0$$

a = 35, b = 2, c = -1

$$D = (2)^2 - 4 \cdot 35 \cdot (-1) = 4 + 140 = 144$$

$$x_1 = \frac{-b + \sqrt{D}}{2a} = \frac{-2 + \sqrt{144}}{2 \cdot 35} = \frac{-2 + 12}{70} = \frac{10}{70} = \frac{1}{7}$$

$$x_2 = \frac{-b - \sqrt{D}}{2a} = \frac{-2 - \sqrt{144}}{2 \cdot 35} = \frac{-2 - 12}{70} = \frac{-14}{70} = -\frac{1}{5}$$

Ответ: $$x_1 = \frac{1}{7}$$, $$x_2 = -\frac{1}{5}$$

д) $$2y^2 - y - 5 = 0$$

a = 2, b = -1, c = -5

$$D = (-1)^2 - 4 \cdot 2 \cdot (-5) = 1 + 40 = 41$$

$$y_1 = \frac{-b + \sqrt{D}}{2a} = \frac{1 + \sqrt{41}}{2 \cdot 2} = \frac{1 + \sqrt{41}}{4}$$

$$y_2 = \frac{-b - \sqrt{D}}{2a} = \frac{1 - \sqrt{41}}{2 \cdot 2} = \frac{1 - \sqrt{41}}{4}$$

Ответ: $$y_1 = \frac{1 + \sqrt{41}}{4}$$, $$y_2 = \frac{1 - \sqrt{41}}{4}$$

e) $$16x^2 - 8x + 1 = 0$$

a = 16, b = -8, c = 1

$$D = (-8)^2 - 4 \cdot 16 \cdot 1 = 64 - 64 = 0$$

$$x = \frac{-b}{2a} = \frac{8}{2 \cdot 16} = \frac{8}{32} = \frac{1}{4}$$

Ответ: $$x = \frac{1}{4}$$