Evaluate the following expressions: \(\frac{x+3y}{xy} - \frac{2y}{xy}\) \(\frac{a-2b}{4a^2} + \frac{a+2b}{4a^2}\)

Решение:

1. \(\frac{x+3y}{xy} - \frac{2y}{xy} = \frac{x+3y-2y}{xy} = \frac{x+y}{xy}\)
2. \(\frac{a-2b}{4a^2} + \frac{a+2b}{4a^2} = \frac{a-2b+a+2b}{4a^2} = \frac{2a}{4a^2} = \frac{1}{2a}\)

Ответ: \(\frac{x+y}{xy}\); \(\frac{1}{2a}\).