13. Даны векторы Ӣ (3; −3) и Б (-16; 8). Найдите координаты вектора: 1) 2a +-6; 2 2)-+; ← 3 4 3) а-б. 5 8

Ответ: 1) \(2\overrightarrow{a} + \frac{1}{2}\overrightarrow{b} = (-2; -2)\); 2) \(-\frac{1}{3}\overrightarrow{a} + \frac{3}{4}\overrightarrow{b} = (-13; 7)\); 3) \(\overrightarrow{a} - \frac{5}{8}\overrightarrow{b} = (13; -8)\)

Дано: \(\overrightarrow{a} = (3; -3)\), \(\overrightarrow{b} = (-16; 8)\)

1) \(2\overrightarrow{a} + \frac{1}{2}\overrightarrow{b} = 2(3; -3) + \frac{1}{2}(-16; 8) = (6; -6) + (-8; 4) = (-2; -2)\)

2) \(-\frac{1}{3}\overrightarrow{a} + \frac{3}{4}\overrightarrow{b} = -\frac{1}{3}(3; -3) + \frac{3}{4}(-16; 8) = (-1; 1) + (-12; 6) = (-13; 7)\)

3) \(\overrightarrow{a} - \frac{5}{8}\overrightarrow{b} = (3; -3) - \frac{5}{8}(-16; 8) = (3; -3) - (-10; 5) = (13; -8)\)

Ответ: 1) \(2\overrightarrow{a} + \frac{1}{2}\overrightarrow{b} = (-2; -2)\); 2) \(-\frac{1}{3}\overrightarrow{a} + \frac{3}{4}\overrightarrow{b} = (-13; 7)\); 3) \(\overrightarrow{a} - \frac{5}{8}\overrightarrow{b} = (13; -8)\)