Решение:
1. Вычисление первого выражения:
- \(3 \frac{2}{3} + 1 \frac{3}{4} = \frac{11}{3} + \frac{7}{4} = \frac{44 + 21}{12} = \frac{65}{12}\)
- \(6 \frac{7}{12} - 2 \frac{1}{4} = \frac{79}{12} - \frac{9}{4} = \frac{79 - 27}{12} = \frac{52}{12} = \frac{13}{3}\)
- \(\frac{65}{12} : \frac{13}{3} = \frac{65}{12} \cdot \frac{3}{13} = \frac{5 \cdot 1}{4 \cdot 1} = \frac{5}{4}\)
- \(\frac{5}{4} \cdot 0,8 = \frac{5}{4} \cdot \frac{4}{5} = 1\)
2. Вычисление второго выражения:
- \(4 \frac{2}{5} : 1 \frac{3}{5} = \frac{22}{5} : \frac{8}{5} = \frac{22}{5} \cdot \frac{5}{8} = \frac{22}{8} = \frac{11}{4}\)
- \(2 \frac{4}{7} - 8 \frac{1}{2} : 14 = \frac{18}{7} - \frac{17}{2} : 14 = \frac{18}{7} - \frac{17}{28} = \frac{72 - 17}{28} = \frac{55}{28}\)
- \(\frac{11}{4} + \frac{55}{28} = \frac{77 + 55}{28} = \frac{132}{28} = \frac{33}{7}\)
- \(2 \frac{3}{8} - 1 \frac{11}{14} = \frac{19}{8} - \frac{25}{14} = \frac{133 - 100}{56} = \frac{33}{56}\)
- \(\frac{33}{7} : \frac{33}{56} = \frac{33}{7} \cdot \frac{56}{33} = 8\)
3. Нахождение 40% значения выражения:
- \(3 \frac{1}{4} + 3 \frac{5}{6} = \frac{13}{4} + \frac{23}{6} = \frac{39 + 46}{12} = \frac{85}{12}\)
- \(5 \frac{3}{4} - 3 \frac{2}{3} = \frac{23}{4} - \frac{11}{3} = \frac{69 - 44}{12} = \frac{25}{12}\)
- \(\frac{85}{12} : \frac{25}{12} = \frac{85}{12} \cdot \frac{12}{25} = \frac{85}{25} = \frac{17}{5}\)
- \(\frac{17}{5} \cdot 40\% = \frac{17}{5} \cdot \frac{40}{100} = \frac{17}{5} \cdot \frac{2}{5} = \frac{34}{25}\)
Ответ: 1; 8; 34/25.