\[ 6 \frac{7}{32} - 2 \frac{11}{48} = (6-2) + (\frac{7}{32} - \frac{11}{48}) = 4 + \frac{21-22}{96} = 4 - \frac{1}{96} = 3 + \frac{96}{96} - \frac{1}{96} = 3 \frac{95}{96} \]
Ответ: 3 95/96