1. Найдем производную функции: $$f'(x) = 3x - \frac{\pi}{2} + 4 \sin x$$.
2. Подставим $$x = \frac{\pi}{6}$$: $$f'(\frac{\pi}{6}) = 3(\frac{\pi}{6}) - \frac{\pi}{2} + 4 \sin(\frac{\pi}{6}) = \frac{\pi}{2} - \frac{\pi}{2} + 4(\frac{1}{2}) = 2$$.
Ответ: 2.