Ответ:

  1. а) \((\frac{9}{4}+\frac{11}{6})(4-\frac{185}{49})=\frac{49}{12}\cdot\frac{11}{49}=\frac{11}{12}\).
  2. б) \((2+\frac{65}{18})(20-\frac{281}{16})=\frac{101}{18}\cdot\frac{39}{16}=\frac{437}{32}=13\frac{21}{32}\).
  3. в) \((2+\frac{17}{9})(\frac{19}{5}-\frac{38}{55})=\frac{35}{9}\cdot\frac{171}{55}=\frac{133}{11}=12\frac{1}{11}\).
  4. г) \(\frac{88}{15}\cdot\frac{5}{11}-\frac{36}{5}\cdot\frac{1}{6}=\frac{8}{3}-\frac{6}{5}=\frac{22}{15}=1\frac{7}{15}\).

Ответ: а) \(\frac{11}{12}\); б) \(13\frac{21}{32}\); в) \(12\frac{1}{11}\); г) \(1\frac{7}{15}\).