1.79 б) Вычислите: \(39:\left(\frac38+\frac16\right)+\left(\frac3{10}\right)^2\cdot\left(\frac23-\frac7{18}\right)\).

\[\frac38+\frac16=\frac9{24}+\frac4{24}=\frac{13}{24}\]

\[39:\frac{13}{24}=39\cdot\frac{24}{13}=72\]

\[\frac23-\frac7{18}=\frac{12}{18}-\frac7{18}=\frac5{18}\]

\[\left(\frac3{10}\right)^2\cdot\frac5{18}=\frac9{100}\cdot\frac5{18}=\frac1{40}\]

\[72+\frac1{40}=\frac{2881}{40}\]

Ответ: \(\frac{2881}{40}\).