№1 Выполните действия a) $$3^4 - (-1)^4$$; d) $$(-33) \cdot 0{,}027$$; g) $$(-42) \cdot (-\frac{1}{7})^2$$; и) $$-4^2 + (\frac{1}{3})^0$$; з) $$(-\frac{3}{3})^2 + |-3|^3$$; e) $$-10 \cdot 0{,}2$$; m) $$\frac{(-5^4)^4}{(-5)^4}$$; 3) $$(1 - \frac{4}{27}) \cdot (-3)^3$$

a) $$3^4 - (-1)^4 = 81 - 1 = 80$$

d) $$(-33) \cdot 0{,}027 = -0{,}891$$

g) $$(-42) \cdot (-\frac{1}{7})^2 = (-42) \cdot \frac{1}{49} = -\frac{42}{49} = -\frac{6}{7}$$

и) $$-4^2 + (\frac{1}{3})^0 = -16 + 1 = -15$$

з) $$(-\frac{3}{3})^2 + |-3|^3 = (-1)^2 + 3^3 = 1 + 27 = 28$$

e) $$-10 \cdot 0{,}2 = -2$$

m) $$\frac{(-5^4)^4}{(-5)^4} = \frac{(-1)^4 \cdot (5^4)^4}{(-1)^4 \cdot 5^4} = \frac{5^{16}}{5^4} = 5^{16-4} = 5^{12}$$

3) $$(1 - \frac{4}{27}) \cdot (-3)^3 = (\frac{27}{27} - \frac{4}{27}) \cdot (-27) = \frac{23}{27} \cdot (-27) = -23$$