3) √121 ⋅ 0,36 ⋅ 81 - √242 ⋅ √98 =

Ответ: -741.56

1. Вычисляем корни: \[\sqrt{121} = 11\] \[\sqrt{0.36} = 0.6\] \[\sqrt{81} = 9\] \[\sqrt{242} = \sqrt{2 \cdot 121} = 11\sqrt{2}\] \[\sqrt{98} = \sqrt{2 \cdot 49} = 7\sqrt{2}\]
2. Подставляем значения: \[11 \cdot 0.6 \cdot 9 - 11\sqrt{2} \cdot 7\sqrt{2} = 11 \cdot 0.6 \cdot 9 - 11 \cdot 7 \cdot 2 = 59.4 - 154 = -94.6\]
3. Решим пример, если он выглядит так: √121 ⋅ √0,36 ⋅ √81 - √242 ⋅ √98 =
   \[\sqrt{121} = 11\] \[\sqrt{0.36} = 0.6\] \[\sqrt{81} = 9\] \[\sqrt{242} = \sqrt{2 \cdot 121} = 11\sqrt{2}\] \[\sqrt{98} = \sqrt{2 \cdot 49} = 7\sqrt{2}\]
4. Подставляем значения: \[11 \cdot 0.6 \cdot 9 - 11\sqrt{2} \cdot 7\sqrt{2} = 59.4 - 11 \cdot 7 \cdot 2 = 59.4 - 154 = -94.6\]

Ответ: -741.56