439 1) \(\frac{a^2}{a^2+ab}\); 2) \(\frac{pq^3}{p^2q-pq^2}\); 3) \(\frac{7a+14b}{3a+6b}\); 4) \(\frac{5k+15f}{3f+k}\); 5) \(\frac{3a-6b}{12b-6a}\); 6) \(\frac{2m-4n}{16n-8m}\)

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Accepted Answer

Краткое пояснение: Раскладываем числитель и знаменатель на множители, затем сокращаем дробь.

\(\frac{a^2}{a^2+ab} = \frac{a \cdot a}{a(a+b)} = \frac{a}{a+b}\)
\(\frac{pq^3}{p^2q-pq^2} = \frac{pq^3}{pq(p-q)} = \frac{q^2}{p-q}\)
\(\frac{7a+14b}{3a+6b} = \frac{7(a+2b)}{3(a+2b)} = \frac{7}{3}\)
\(\frac{5k+15f}{3f+k} = \frac{5(k+3f)}{3f+k} = 5\)
\(\frac{3a-6b}{12b-6a} = \frac{3(a-2b)}{-6(a-2b)} = -\frac{1}{2}\)
\(\frac{2m-4n}{16n-8m} = \frac{2(m-2n)}{-8(m-2n)} = -\frac{1}{4}\)

Ответ: 1) \(\frac{a}{a+b}\); 2) \(\frac{q^2}{p-q}\); 3) \(\frac{7}{3}\); 4) 5; 5) -\(\frac{1}{2}\); 6) -\(\frac{1}{4}\)