Ответ:
Решение:
- \( 2\sqrt{7} \) и \( \sqrt{7} \cdot 2\sqrt{8} \)
- \( 3\sqrt{6} \) и \( \sqrt{60} \)
- \( 2\sqrt{6} \) и \( \sqrt{21} \)
- \( 3\sqrt{4} \) и \( 6 \)
- \( \sqrt{40} \) и \( 2\sqrt{11} \)
- \( 4\sqrt{2} \) и \( \sqrt{30} \)
- \( 4\sqrt{5} \) и \( \sqrt{80} \)
- \( 2\sqrt{7} \) и \( 5 \)
- \( 6\sqrt{3} \) и \( 10 \)
- \( 3\sqrt{3} \) и \( \sqrt{10} \)
- \( 2\sqrt{3} \) и \( 3\sqrt{2} \)
- \( 8\sqrt{2} \) и \( 8\sqrt{6} \)
- \( -2\sqrt{6} \) и \( -8\sqrt{2} \)
- \( 5\sqrt{3} \) и \( 6\sqrt{2} \)
- \( 3\sqrt{10} \) и \( 7\sqrt{2} \)
- \( -10\sqrt{6} \) и \( -5\sqrt{10} \)
- \( -2\sqrt{8} \) и \( -4\sqrt{2} \)
- \( -2\sqrt{1,1} \) и \( -2\sqrt{1,5} \)
- \( 10\sqrt{20} \) и \( 20\sqrt{10} \)
- \( -0,2\sqrt{5} \) и \( -0,5\sqrt{2} \)
\( 2\sqrt{7} = \sqrt{4}\sqrt{7} = \sqrt{28}\)
\( \sqrt{7} \cdot 2\sqrt{8} = \sqrt{7} \cdot \sqrt{4}\sqrt{8} = \sqrt{7} \cdot \sqrt{32} = \sqrt{224}\)
\( \sqrt{28} < \sqrt{224} \), значит, \( 2\sqrt{7} < \sqrt{7} \cdot 2\sqrt{8} \).
\( 3\sqrt{6} = \sqrt{9}\sqrt{6} = \sqrt{54}\)
\( \sqrt{54} < \sqrt{60} \), значит, \( 3\sqrt{6} < \sqrt{60} \).
\( 2\sqrt{6} = \sqrt{4}\sqrt{6} = \sqrt{24}\)
\( \sqrt{24} > \sqrt{21} \), значит, \( 2\sqrt{6} > \sqrt{21} \).
\( 3\sqrt{4} = 3 \cdot 2 = 6\)
\( 6 = 6 \), значит, \( 3\sqrt{4} = 6 \).
\( 2\sqrt{11} = \sqrt{4}\sqrt{11} = \sqrt{44}\)
\( \sqrt{40} < \sqrt{44} \), значит, \( \sqrt{40} < 2\sqrt{11} \).
\( 4\sqrt{2} = \sqrt{16}\sqrt{2} = \sqrt{32}\)
\( \sqrt{32} > \sqrt{30} \), значит, \( 4\sqrt{2} > \sqrt{30} \).
\( 4\sqrt{5} = \sqrt{16}\sqrt{5} = \sqrt{80}\)
\( \sqrt{80} = \sqrt{80} \), значит, \( 4\sqrt{5} = \sqrt{80} \).
\( 2\sqrt{7} = \sqrt{4}\sqrt{7} = \sqrt{28}\)
\( 5 = \sqrt{25}\)
\( \sqrt{28} > \sqrt{25} \), значит, \( 2\sqrt{7} > 5 \).
\( 6\sqrt{3} = \sqrt{36}\sqrt{3} = \sqrt{108}\)
\( 10 = \sqrt{100}\)
\( \sqrt{108} > \sqrt{100} \), значит, \( 6\sqrt{3} > 10 \).
\( 3\sqrt{3} = \sqrt{9}\sqrt{3} = \sqrt{27}\)
\( \sqrt{27} > \sqrt{10} \), значит, \( 3\sqrt{3} > \sqrt{10} \).
\( 2\sqrt{3} = \sqrt{4}\sqrt{3} = \sqrt{12}\)
\( 3\sqrt{2} = \sqrt{9}\sqrt{2} = \sqrt{18}\)
\( \sqrt{12} < \sqrt{18} \), значит, \( 2\sqrt{3} < 3\sqrt{2} \).
\( 8\sqrt{2} = \sqrt{64}\sqrt{2} = \sqrt{128}\)
\( 8\sqrt{6} = \sqrt{64}\sqrt{6} = \sqrt{384}\)
\( \sqrt{128} < \sqrt{384} \), значит, \( 8\sqrt{2} < 8\sqrt{6} \).
\( -2\sqrt{6} = -\sqrt{4}\sqrt{6} = -\sqrt{24}\)
\( -8\sqrt{2} = -\sqrt{64}\sqrt{2} = -\sqrt{128}\)
\( -\sqrt{24} > -\sqrt{128} \), значит, \( -2\sqrt{6} > -8\sqrt{2} \).
\( 5\sqrt{3} = \sqrt{25}\sqrt{3} = \sqrt{75}\)
\( 6\sqrt{2} = \sqrt{36}\sqrt{2} = \sqrt{72}\)
\( \sqrt{75} > \sqrt{72} \), значит, \( 5\sqrt{3} > 6\sqrt{2} \).
\( 3\sqrt{10} = \sqrt{9}\sqrt{10} = \sqrt{90}\)
\( 7\sqrt{2} = \sqrt{49}\sqrt{2} = \sqrt{98}\)
\( \sqrt{90} < \sqrt{98} \), значит, \( 3\sqrt{10} < 7\sqrt{2} \).
\( -10\sqrt{6} = -\sqrt{100}\sqrt{6} = -\sqrt{600}\)
\( -5\sqrt{10} = -\sqrt{25}\sqrt{10} = -\sqrt{250}\)
\( -\sqrt{600} < -\sqrt{250} \), значит, \( -10\sqrt{6} < -5\sqrt{10} \).
\( -2\sqrt{8} = -\sqrt{4}\sqrt{8} = -\sqrt{32}\)
\( -4\sqrt{2} = -\sqrt{16}\sqrt{2} = -\sqrt{32}\)
\( -\sqrt{32} = -\sqrt{32} \), значит, \( -2\sqrt{8} = -4\sqrt{2} \).
\( -2\sqrt{1,1} = -\sqrt{4}\sqrt{1,1} = -\sqrt{4,4}\)
\( -2\sqrt{1,5} = -\sqrt{4}\sqrt{1,5} = -\sqrt{6}\)
\( -\sqrt{4,4} > -\sqrt{6} \), значит, \( -2\sqrt{1,1} > -2\sqrt{1,5} \).
\( 10\sqrt{20} = \sqrt{100}\sqrt{20} = \sqrt{2000}\)
\( 20\sqrt{10} = \sqrt{400}\sqrt{10} = \sqrt{4000}\)
\( \sqrt{2000} < \sqrt{4000} \), значит, \( 10\sqrt{20} < 20\sqrt{10} \).
\( -0,2\sqrt{5} = -\sqrt{0,04}\sqrt{5} = -\sqrt{0,2}\)
\( -0,5\sqrt{2} = -\sqrt{0,25}\sqrt{2} = -\sqrt{0,5}\)
\( -\sqrt{0,2} > -\sqrt{0,5} \), значит, \( -0,2\sqrt{5} > -0,5\sqrt{2} \).
