6. 2) $$(3x-5)(2x + 7) = (3x + 1)(2x-3) + 4x$$.

$$(3x-5)(2x + 7) = (3x + 1)(2x-3) + 4x$$ $$6x^2 + 21x - 10x - 35 = 6x^2 - 9x + 2x - 3 + 4x$$ $$6x^2 + 11x - 35 = 6x^2 - 3x - 3$$ $$11x - 35 = -3x - 3$$ $$14x = 32$$ $$x = \frac{32}{14} = \frac{16}{7}$$ **Ответ:** $$x = \frac{16}{7}$$