1) \[\frac{17-12x}{x} - \frac{10}{x} = \frac{17-12x-10}{x} = \frac{7-12x}{x}\]
2) \[\frac{12p-1}{3p^2} - \frac{1+3p}{3p^2} = \frac{12p-1-(1+3p)}{3p^2} = \frac{12p-1-1-3p}{3p^2} = \frac{9p-2}{3p^2}\]
3) \[\frac{6y-3}{5y} - \frac{y+2}{5y} = \frac{6y-3-(y+2)}{5y} = \frac{6y-3-y-2}{5y} = \frac{5y-5}{5y} = \frac{5(y-1)}{5y} = \frac{y-1}{y}\]
4) \[\frac{5b}{6} - \frac{3a-2b}{6} = \frac{5b-(3a-2b)}{6} = \frac{5b-3a+2b}{6} = \frac{7b-3a}{6}\]
5) \[\frac{5y-3}{7y} - \frac{3y+2}{7y} = \frac{5y-3-(3y+2)}{7y} = \frac{5y-3-3y-2}{7y} = \frac{2y-5}{7y}\]
6) \[\frac{11x-5}{14x} + \frac{3x-2}{14x} = \frac{11x-5+3x-2}{14x} = \frac{14x-7}{14x} = \frac{7(2x-1)}{14x} = \frac{2x-1}{2x}\]
7) \[\frac{7y-13}{10y} - \frac{2y+3}{10y} = \frac{7y-13-(2y+3)}{10y} = \frac{7y-13-2y-3}{10y} = \frac{5y-16}{10y}\]
8) \[\frac{8c+25}{6c} + \frac{5-2c}{6c} = \frac{8c+25+5-2c}{6c} = \frac{6c+30}{6c} = \frac{6(c+5)}{6c} = \frac{c+5}{c}\]
Ответ: Выше представлены решения каждого пункта задания.