Контрольные задания >
126. Выполните вычитание.
1) $$5\frac{8}{51}-3\frac{5}{17}=5\frac{8}{51}-3\frac{15}{51}=4\frac{59}{51}-3\frac{15}{51}=$$
2) $$4\frac{2}{9}-1\frac{17}{36}=$$
3) $$6\frac{2}{3}-2\frac{6}{7}=$$
4) $$3\frac{1}{6}-2\frac{3}{8}=$$
5) $$9\frac{7}{20}-4\frac{9}{25}=$$
123. Найдите сумму.
1) $$3\frac{7}{16}+2\frac{5}{32}=3+\frac{7}{16}+2+\frac{5}{32}=(+)+(+)=$$
2) $$1\frac{1}{12}+3\frac{4}{9}=$$
3) $$4\frac{1}{6}+5\frac{3}{14}+6\frac{2}{21}=$$ Вопрос:
126. Выполните вычитание.
1) $$5\frac{8}{51}-3\frac{5}{17}=5\frac{8}{51}-3\frac{15}{51}=4\frac{59}{51}-3\frac{15}{51}=$$
2) $$4\frac{2}{9}-1\frac{17}{36}=$$
3) $$6\frac{2}{3}-2\frac{6}{7}=$$
4) $$3\frac{1}{6}-2\frac{3}{8}=$$
5) $$9\frac{7}{20}-4\frac{9}{25}=$$
123. Найдите сумму.
1) $$3\frac{7}{16}+2\frac{5}{32}=3+\frac{7}{16}+2+\frac{5}{32}=(+)+(+)=$$
2) $$1\frac{1}{12}+3\frac{4}{9}=$$
3) $$4\frac{1}{6}+5\frac{3}{14}+6\frac{2}{21}=$$
Ответ:
Решение заданий на вычитание и сложение смешанных чисел.
126. Выполните вычитание.
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$$5\frac{8}{51}-3\frac{5}{17}=5\frac{8}{51}-3\frac{5 \cdot 3}{17 \cdot 3}=5\frac{8}{51}-3\frac{15}{51}=4\frac{59}{51}-3\frac{15}{51}=1\frac{44}{51}$$
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$$4\frac{2}{9}-1\frac{17}{36}=4\frac{2 \cdot 4}{9 \cdot 4}-1\frac{17}{36}=4\frac{8}{36}-1\frac{17}{36}=3\frac{44}{36}-1\frac{17}{36}=2\frac{27}{36}=2\frac{3}{4}$$
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$$6\frac{2}{3}-2\frac{6}{7}=6\frac{2 \cdot 7}{3 \cdot 7}-2\frac{6 \cdot 3}{7 \cdot 3}=6\frac{14}{21}-2\frac{18}{21}=5\frac{35}{21}-2\frac{18}{21}=3\frac{17}{21}$$
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$$3\frac{1}{6}-2\frac{3}{8}=3\frac{1 \cdot 4}{6 \cdot 4}-2\frac{3 \cdot 3}{8 \cdot 3}=3\frac{4}{24}-2\frac{9}{24}=2\frac{28}{24}-2\frac{9}{24}=\frac{19}{24}$$
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$$9\frac{7}{20}-4\frac{9}{25}=9\frac{7 \cdot 5}{20 \cdot 5}-4\frac{9 \cdot 4}{25 \cdot 4}=9\frac{35}{100}-4\frac{36}{100}=8\frac{135}{100}-4\frac{36}{100}=4\frac{99}{100}$$
123. Найдите сумму.
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$$3\frac{7}{16}+2\frac{5}{32}=3+\frac{7}{16}+2+\frac{5}{32}=(3+2)+(\frac{7 \cdot 2}{16 \cdot 2}+ \frac{5}{32})=5+(\frac{14}{32}+ \frac{5}{32})=5+\frac{19}{32}=5\frac{19}{32}$$
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$$1\frac{1}{12}+3\frac{4}{9}=1\frac{1 \cdot 3}{12 \cdot 3}+3\frac{4 \cdot 4}{9 \cdot 4}=1\frac{3}{36}+3\frac{16}{36}=4\frac{19}{36}$$
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$$4\frac{1}{6}+5\frac{3}{14}+6\frac{2}{21}=4\frac{1 \cdot 7}{6 \cdot 7}+5\frac{3 \cdot 3}{14 \cdot 3}+6\frac{2 \cdot 2}{21 \cdot 2}=4\frac{7}{42}+5\frac{9}{42}+6\frac{4}{42}=15\frac{20}{42}=15\frac{10}{21}$$
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