Преобразуем смешанные числа в неправильные дроби:
- $$2\frac{63}{100} = \frac{2 \cdot 100 + 63}{100} = \frac{200 + 63}{100} = \frac{263}{100}$$
- $$3\frac{9}{10} = \frac{3 \cdot 10 + 9}{10} = \frac{30 + 9}{10} = \frac{39}{10}$$
- $$6\frac{1}{6} = \frac{6 \cdot 6 + 1}{6} = \frac{36 + 1}{6} = \frac{37}{6}$$
- $$1\frac{7}{9} = \frac{1 \cdot 9 + 7}{9} = \frac{9 + 7}{9} = \frac{16}{9}$$
- $$2\frac{4}{13} = \frac{2 \cdot 13 + 4}{13} = \frac{26 + 4}{13} = \frac{30}{13}$$
- $$4\frac{2}{3} = \frac{4 \cdot 3 + 2}{3} = \frac{12 + 2}{3} = \frac{14}{3}$$
- $$1\frac{51}{100} = \frac{1 \cdot 100 + 51}{100} = \frac{100 + 51}{100} = \frac{151}{100}$$
- $$5\frac{1}{10} = \frac{5 \cdot 10 + 1}{10} = \frac{50 + 1}{10} = \frac{51}{10}$$
- $$3\frac{4}{11} = \frac{3 \cdot 11 + 4}{11} = \frac{33 + 4}{11} = \frac{37}{11}$$
- $$2\frac{9}{10} = \frac{2 \cdot 10 + 9}{10} = \frac{20 + 9}{10} = \frac{29}{10}$$
- $$2\frac{1}{12} = \frac{2 \cdot 12 + 1}{12} = \frac{24 + 1}{12} = \frac{25}{12}$$
- $$3\frac{5}{9} = \frac{3 \cdot 9 + 5}{9} = \frac{27 + 5}{9} = \frac{32}{9}$$
- $$1\frac{91}{100} = \frac{1 \cdot 100 + 91}{100} = \frac{100 + 91}{100} = \frac{191}{100}$$
- $$2\frac{3}{8} = \frac{2 \cdot 8 + 3}{8} = \frac{16 + 3}{8} = \frac{19}{8}$$
- $$4\frac{1}{10} = \frac{4 \cdot 10 + 1}{10} = \frac{40 + 1}{10} = \frac{41}{10}$$