Решение задания 2.249

a) $$4\frac{13}{24}+1\frac{1}{8}-3\frac{3}{24} = 4\frac{13}{24}+1\frac{3}{24}-3\frac{3}{24} = 5\frac{16}{24}-3\frac{3}{24} = (5-3) + (\frac{16}{24}-\frac{3}{24}) = 2 + \frac{13}{24} = 2\frac{13}{24}$$

б) $$5\frac{1}{2}-\frac{7}{12}-2\frac{3}{10} = 5\frac{30}{60}-\frac{35}{60}-2\frac{18}{60} = 4\frac{90}{60}-\frac{35}{60}-2\frac{18}{60} = 4\frac{55}{60}-2\frac{18}{60} = (4-2) + (\frac{55}{60}-\frac{18}{60}) = 2 + \frac{37}{60} = 2\frac{37}{60}$$

в) $$1+3\frac{5}{6}=7\frac{1}{6}-2\frac{2}{3}$$

$$4\frac{5}{6}=7\frac{1}{6}-2\frac{4}{6}$$

$$4\frac{5}{6}=4\frac{3}{6}$$ - неверно

Ответ: a) $$2\frac{13}{24}$$; б) $$2\frac{37}{60}$$; в) неверно