Решение задания 2.246

a) $$38\frac{1}{8}+4\frac{5}{24} = 38\frac{3}{24}+4\frac{5}{24} = (38+4) + (\frac{3}{24}+\frac{5}{24}) = 42 + \frac{8}{24} = 42 + \frac{1}{3} = 42\frac{1}{3}$$

б) $$4\frac{7}{75}+6\frac{17}{45} = 4\frac{21}{225}+6\frac{85}{225} = (4+6) + (\frac{21}{225}+ \frac{85}{225}) = 10 + \frac{106}{225} = 10\frac{106}{225}$$

д) $$28\frac{5}{9}+13\frac{3}{4} = 28\frac{20}{36}+13\frac{27}{36} = (28+13) + (\frac{20}{36}+\frac{27}{36}) = 41 + \frac{47}{36} = 41 + 1\frac{11}{36} = 42\frac{11}{36}$$

e) $$\frac{4}{7}+2\frac{3}{5} = \frac{4}{7}+2\frac{21}{35} = \frac{20}{35}+2\frac{21}{35} = 2 + \frac{20}{35}+\frac{21}{35} = 2 + \frac{41}{35} = 2 + 1\frac{6}{35} = 3\frac{6}{35}$$

ж) $$9+2\frac{2}{9} = 11\frac{2}{9}$$

з) $$3\frac{11}{24}+1\frac{1}{6} = 3\frac{11}{24}+1\frac{4}{24} = (3+1) + (\frac{11}{24}+\frac{4}{24}) = 4 + \frac{15}{24} = 4 + \frac{5}{8} = 4\frac{5}{8}$$

Ответ: a) $$42\frac{1}{3}$$; б) $$10\frac{106}{225}$$; д) $$42\frac{11}{36}$$; e) $$3\frac{6}{35}$$; ж) $$11\frac{2}{9}$$; з) $$4\frac{5}{8}$$