a)
\( 1\frac{2}{3} + 3\frac{1}{3} - 2\frac{1}{3} = \frac{5}{3} + \frac{10}{3} - \frac{7}{3} = \frac{5+10-7}{3} = \frac{8}{3} = 2\frac{2}{3} \)
б)
\( 2\frac{1}{6} + 3\frac{2}{3} + 4\frac{5}{6} = 2\frac{1}{6} + 3\frac{4}{6} + 4\frac{5}{6} = (2+3+4) + \frac{1+4+5}{6} = 9 + \frac{10}{6} = 9 + 1\frac{4}{6} = 9 + 1\frac{2}{3} = 10\frac{2}{3} \)
в)
\( 7\frac{5}{12} - 1\frac{5}{6} + 3\frac{1}{24} = 7\frac{10}{24} - 1\frac{20}{24} + 3\frac{1}{24} = (7-1+3) + \frac{10-20+1}{24} = 9 + \frac{-9}{24} = 9 - \frac{9}{24} = 9 - \frac{3}{8} = 8\frac{5}{8} \)
г)
\( 9\frac{7}{18} - 6\frac{2}{36} + 11\frac{2}{9} = 9\frac{14}{36} - 6\frac{2}{36} + 11\frac{8}{36} = (9-6+11) + \frac{14-2+8}{36} = 14 + \frac{20}{36} = 14 + \frac{5}{9} = 14\frac{5}{9} \)
Ответ: а) \(2\frac{2}{3}\); б) \(10\frac{2}{3}\); в) \(8\frac{5}{8}\); г) \(14\frac{5}{9}\).