a. $$(1\frac{1}{24}-\frac{5}{12})\times(4\frac{1}{8}-3\frac{5}{24})=(1\frac{1}{24}-\frac{10}{24})\times(4\frac{3}{24}-3\frac{5}{24})=\frac{25}{24}-\frac{10}{24}\times\frac{99}{24}-\frac{77}{24}=\frac{15}{24}\times\frac{22}{24}=\frac{330}{576}=\frac{55}{96}$$
Ответ:$$\frac{55}{96}$$