a. $$(14\frac{2}{3}-5\frac{5}{9})-(3\frac{7}{8}+4\frac{5}{6})+(10\frac{3}{4}-4\frac{4}{9})=(14\frac{6}{9}-5\frac{5}{9})-(3\frac{21}{24}+4\frac{20}{24})+(10\frac{27}{36}-4\frac{16}{36})=8\frac{1}{9}-7\frac{41}{24}+6\frac{11}{36}=8\frac{8}{72}-7\frac{123}{72}+6\frac{22}{72}=7\frac{80}{72}-7\frac{123}{72}+6\frac{22}{72}=6\frac{79}{72}+6\frac{22}{72}=12\frac{101}{72}=13\frac{29}{72}$$
Ответ:$$13\frac{29}{72}$$