а) $$7 \frac{8}{9} - 3 \frac{5}{9} = (7 - 3) + (\frac{8}{9} - \frac{5}{9}) = 4 + \frac{3}{9} = 4 + \frac{1}{3} = 4 \frac{1}{3}$$
б) $$5 \frac{5}{12} + 2 \frac{1}{12} = (5 + 2) + (\frac{5}{12} + \frac{1}{12}) = 7 + \frac{6}{12} = 7 + \frac{1}{2} = 7 \frac{1}{2}$$
в) $$29 \frac{11}{21} - 29 \frac{5}{21} = (29 - 29) + (\frac{11}{21} - \frac{5}{21}) = 0 + \frac{6}{21} = \frac{2}{7}$$
г) $$6 \frac{3}{10} + 7 \frac{5}{10} = (6 + 7) + (\frac{3}{10} + \frac{5}{10}) = 13 + \frac{8}{10} = 13 + \frac{4}{5} = 13 \frac{4}{5}$$
Ответ: а) $$4 \frac{1}{3}$$; б) $$7 \frac{1}{2}$$; в) $$\frac{2}{7}$$; г) $$13 \frac{4}{5}$$