Ответ:
\[- 7; - 4; - 1;\ldots\]
\[a_{1} = - 7;\ \ a_{2} = - 4;\]
\[d = a_{2} - a_{1} = - 4 + 7 = 3.\]
\[S_{6} = \frac{2a_{1} + d(n - 1)}{2} \cdot n =\]
\[= \frac{- 14 + 3(6 - 1)}{2} \cdot 6 =\]
\[= ( - 14 + 15) \cdot 3 = 3.\]
\[- 7; - 4; - 1;\ldots\]
\[a_{1} = - 7;\ \ a_{2} = - 4;\]
\[d = a_{2} - a_{1} = - 4 + 7 = 3.\]
\[S_{6} = \frac{2a_{1} + d(n - 1)}{2} \cdot n =\]
\[= \frac{- 14 + 3(6 - 1)}{2} \cdot 6 =\]
\[= ( - 14 + 15) \cdot 3 = 3.\]